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RRB Recruitment 2025: The Railway Recruitment Board (RRB) has extended the last date to register for the ministerial and isolated categories recruitment 2025. The last date to apply for the RRB posts is now February 16, 2025. Initially, it was February 7, 2025. The official notice can be checked by candidates on the official website of regional RRBs.
The last date for payment of the application fee has also been revised. Applicants will now be able to pay the fee until February 17, 2025. For those who wish to modify their application details, the modification window will be available from February 19 to February 28, 2025.
Step 1: Visit the official website, rrbapply.gov.in
Step 2: Create an account. Fill in the details required for account creation.
Step 3: Fill in the details.
Step 4: Pay the fee amount
Step 5: Submit and download the application form
To avoid last minute rush, the RRB has advised the candidates to register and submit the online application much
before the closing date since there may be a possibility of inability or failure to log on to the website of RRB concerned on account of heavy load on the internet or website during the last days of online registration.
The RRB has also shared helpline numbers and email ID for candidates for any queries related to submission of application. These are 9592001188, 01725653333 and rrb.help@csc.gov.in. The helpdesks will work between 10 am and 5 pm on all working days.
The RRB recruitment 2025 selection process comprises of a single stage computer-based test, performance test or teaching skill test, translation test (as applicable) and document verification and medical examination. The question paper for single stage CBT will be of 90 minutes duration for 100 questions and 120 minutes for PwBD candidates who are availing the scribe facility. Marks will be normalised for all the stages of exam involving multiple sessions.
There will also be negative marking for incorrect answer in CBTs. Deduction of 1/3rd of the marks allotted for each question shall be made for each wrong answer.
